net,rcu: convert call_rcu(rps_map_release) to kfree_rcu() (f6f80238) · Commits · 戴 / test

The rcu callback rps_map_release() just calls a kfree(), so we use kfree_rcu() instead of the call_rcu(rps_map_release). Signed-off-by:

net/core/net-sysfs.c

+2 −9

Original line number	Diff line number	Diff line
		@@ -565,13 +565,6 @@ static ssize_t show_rps_map(struct netdev_rx_queue *queue,
		return len;
		}

		static void rps_map_release(struct rcu_head *rcu)
		{
		struct rps_map *map = container_of(rcu, struct rps_map, rcu);

		kfree(map);
		}

		static ssize_t store_rps_map(struct netdev_rx_queue *queue,
		struct rx_queue_attribute *attribute,
		const char *buf, size_t len)
		@@ -619,7 +612,7 @@ static ssize_t store_rps_map(struct netdev_rx_queue *queue,
		spin_unlock(&rps_map_lock);

		if (old_map)
		call_rcu(&old_map->rcu, rps_map_release);
		kfree_rcu(old_map, rcu);

		free_cpumask_var(mask);
		return len;
		@@ -728,7 +721,7 @@ static void rx_queue_release(struct kobject *kobj)
		map = rcu_dereference_raw(queue->rps_map);
		if (map) {
		RCU_INIT_POINTER(queue->rps_map, NULL);
		call_rcu(&map->rcu, rps_map_release);
		kfree_rcu(map, rcu);
		}

		flow_table = rcu_dereference_raw(queue->rps_flow_table);