Commit 7f05538a authored Jan 26, 2016 by Russell King Committed by Ulf Hansson Feb 29, 2016

mmc: sdhci: fix data timeout (part 2)



The calculation for the timeout based on the number of card clocks is
incorrect.  The calculation assumed:

	timeout in microseconds = clock cycles / clock in Hz

which is clearly a several orders of magnitude wrong.  Fix this by
multiplying the clock cycles by 1000000 prior to dividing by the Hz
based clock.  Also, as per part 1, ensure that the division rounds
up.

As this needs 64-bit math via do_div(), avoid it if the clock cycles
is zero.

Signed-off-by: Russell King <rmk+kernel@arm.linux.org.uk>
Signed-off-by: Adrian Hunter <adrian.hunter@intel.com>
Cc: stable@vger.kernel.org # v3.15+
Tested-by: Gregory CLEMENT <gregory.clement@free-electrons.com>
Signed-off-by: Ulf Hansson <ulf.hansson@linaro.org>

parent fafcfda9

drivers/mmc/host/sdhci.c

+13 −2

Original line number	Diff line number	Diff line
		@@ -636,8 +636,19 @@ static u8 sdhci_calc_timeout(struct sdhci_host host, struct mmc_command cmd)
		target_timeout = cmd->busy_timeout * 1000;
		else {
		target_timeout = DIV_ROUND_UP(data->timeout_ns, 1000);
		if (host->clock)
		target_timeout += data->timeout_clks / host->clock;
		if (host->clock && data->timeout_clks) {
		unsigned long long val;

		/*
		* data->timeout_clks is in units of clock cycles.
		* host->clock is in Hz. target_timeout is in us.
		* Hence, us = 1000000 * cycles / Hz. Round up.
		*/
		val = 1000000 * data->timeout_clks;
		if (do_div(val, host->clock))
		target_timeout++;
		target_timeout += val;
		}
		}

		/*

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