crypto: wait for a full jiffy in do_xor_speed (6a328475) · Commits · 戴 / test

In the existing do_xor_speed(), there is no guarantee that we actually run do_2() for a full jiffy. We get the current jiffy, then run do_2() until the next jiffy. Instead, let's get the current jiffy, then wait until the next jiffy to start our test. Signed-off-by:

Jim Kukunas <james.t.kukunas@linux.intel.com> Signed-off-by:

NeilBrown <neilb@suse.de>

crypto/xor.c

+5 −3

Original line number	Diff line number	Diff line
		@@ -63,7 +63,7 @@ static void
		do_xor_speed(struct xor_block_template tmpl, void b1, void *b2)
		{
		int speed;
		unsigned long now;
		unsigned long now, j;
		int i, count, max;

		tmpl->next = template_list;
		@@ -76,9 +76,11 @@ do_xor_speed(struct xor_block_template tmpl, void b1, void *b2)
		*/
		max = 0;
		for (i = 0; i < 5; i++) {
		now = jiffies;
		j = jiffies;
		count = 0;
		while (jiffies == now) {
		while ((now = jiffies) == j)
		cpu_relax();
		while (time_before(jiffies, now + 1)) {
		mb(); /* prevent loop optimzation */
		tmpl->do_2(BENCH_SIZE, b1, b2);
		mb();

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