do not require the LAMMPS shared library when loading the python wrapper from inside LAMMPS (0b426dad) · Commits · 郑智淋 / lammps

Thanks to Giacomo Fiorin for figuring this out with NAMD/Colvars. This requires linking with -Xlinker -export-dynamic or equivalent, which is the default when using python-config to provide linker flags. We will fall back to loading the DSO in case the initial load fails.

python/lammps.py

+14 −7

Original line number	Diff line number	Diff line
		@@ -58,6 +58,13 @@ class lammps(object):
		# determine module location

		modpath = dirname(abspath(getsourcefile(lambda:0)))
		self.lib = None

		# if a pointer to a LAMMPS object is handed in, all symbols should already be available.
		try:
		if ptr: self.lib = CDLL("",RTLD_GLOBAL)
		except:
		self.lib = None

		# load liblammps.so unless name is given.
		# e.g. if name = "g++", load liblammps_g++.so
		@@ -66,7 +73,7 @@ class lammps(object):
		# does not need to be set for regular installations.
		# fall back to loading with a relative path, which typically
		# requires LD_LIBRARY_PATH to be set appropriately.

		if not self.lib:
		try:
		if not name: self.lib = CDLL(join(modpath,"liblammps.so"),RTLD_GLOBAL)
		else: self.lib = CDLL(join(modpath,"liblammps_%s.so" % name),RTLD_GLOBAL)

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